NW | 25-ITP-Sep | TzeMing Ho | Sprint 1 | sprint-1-exercises #792
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TzeMingHo
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| // return [] if arr is [] | ||
| if (arr.length === 0) return []; |
| // return [] if arr is [] | ||
| if (arr.length === 0) return []; | ||
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| return [...new Set(arr)]; |
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What's special about Set that solves our problem here?
| test("given an array with no duplicates, it returns the original array", () => { | ||
| expect(dedupe(["a", "b", "c"])).toEqual(["a", "b", "c"]); | ||
| expect(dedupe([1, 2, 3])).toEqual([1, 2, 3]); | ||
| expect(dedupe([{ key1: "a" }, { key2: "b" }, { key3: "c" }])).toEqual([ |
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challenge: what would you expect if I did this?
dedupe([{ key1: "a" }, { key1: "a" }, { key1: "a" }])| return 0; | ||
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| return elements.reduce((acc, num) => acc + num, 0); |
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Could you explain what this reduce function is doing?
CameronDowner
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I have created a function for finding the median, both tests and functions in the implement exercise, refactored the loop function, and found out the frequency of time travel.