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trees/subtree: Add MTC subtree primitives #8808
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| Original file line number | Diff line number | Diff line change | ||||||||
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| @@ -0,0 +1,268 @@ | ||||||||||
| package subtree | ||||||||||
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||||||||||
| import ( | ||||||||||
| "fmt" | ||||||||||
| "math/bits" | ||||||||||
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|
||||||||||
| "golang.org/x/mod/sumdb/tlog" | ||||||||||
| ) | ||||||||||
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||||||||||
| // valid reports whether [start, end) is a valid subtree per the MTC draft | ||||||||||
| // section 4.1 Definition of a Subtree: 0 <= start < end and start is a multiple | ||||||||||
| // of BIT_CEIL(end - start). | ||||||||||
| func valid(start, end int64) bool { | ||||||||||
| if start < 0 || start >= end { | ||||||||||
| // A subtree must have 0 <= start < end. | ||||||||||
| return false | ||||||||||
| } | ||||||||||
| // start must be a multiple of BIT_CEIL(end-start). bits.Len64(x) is the bit | ||||||||||
| // width of x, so 1<<bits.Len64(x) is the smallest power of two strictly | ||||||||||
| // above x, an exclusive ceiling. BIT_CEIL(x) is inclusive, the smallest | ||||||||||
| // power of two at least x, so we apply it to end-start-1. | ||||||||||
| bitCeil := uint64(1) << bits.Len64(uint64(end-start-1)) //nolint:gosec // G115: the start >= end check above leaves end-start positive, so end-start-1 is non-negative. | ||||||||||
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||||||||||
| // bitCeil-1 masks the bits below bitCeil, so start & (bitCeil-1) is zero | ||||||||||
| // exactly when start is a multiple of bitCeil. | ||||||||||
| return uint64(start)&(bitCeil-1) == 0 | ||||||||||
| } | ||||||||||
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||||||||||
| // completeSubtree reports whether [start, end) is a complete subtree (a valid | ||||||||||
| // subtree with a power-of-two size), and if so its level. | ||||||||||
| func completeSubtree(start, end int64) (level int, ok bool) { | ||||||||||
| size := end - start | ||||||||||
| if !valid(start, end) || bits.OnesCount64(uint64(size)) != 1 { //nolint:gosec // G115: valid ensures start < end, so size is positive. | ||||||||||
| return 0, false | ||||||||||
| } | ||||||||||
| return bits.TrailingZeros64(uint64(size)), true //nolint:gosec // G115: valid ensures start < end, so size is positive. | ||||||||||
| } | ||||||||||
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||||||||||
| // splitPoint returns where to split the subtree [start, end) into a complete | ||||||||||
| // subtree on the left and a possibly ragged one on the right. This is the mid | ||||||||||
| // in draft-ietf-plants-merkle-tree-certs section 4.5.1. | ||||||||||
| func splitPoint(start, end int64) int64 { | ||||||||||
| if end-start <= 1 { | ||||||||||
| panic(fmt.Sprintf("splitPoint: end-start must be > 1, got %d", end-start)) | ||||||||||
| } | ||||||||||
| return start + int64(1)<<(bits.Len64(uint64(end-start-1))-1) //nolint:gosec // G115: end-start > 1, so end-start-1 is positive. | ||||||||||
| } | ||||||||||
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|
||||||||||
| // combineSubtreeRoots combines subtree roots, in the order | ||||||||||
| // completeSubtreeIndexes lists them, into MTH(D[start:end]). It returns the | ||||||||||
| // hash and the unconsumed remainder. | ||||||||||
| func combineSubtreeRoots(start, end int64, hashes []tlog.Hash) (tlog.Hash, []tlog.Hash) { | ||||||||||
| _, ok := completeSubtree(start, end) | ||||||||||
| if ok { | ||||||||||
| return hashes[0], hashes[1:] | ||||||||||
| } | ||||||||||
| // completeSubtree accepts single leaves, and the input is always a valid | ||||||||||
| // subtree (end > start), so end-start >= 2 here. | ||||||||||
| mid := splitPoint(start, end) | ||||||||||
| left, rest := combineSubtreeRoots(start, mid, hashes) | ||||||||||
| right, rest := combineSubtreeRoots(mid, end, rest) | ||||||||||
| return tlog.NodeHash(left, right), rest | ||||||||||
| } | ||||||||||
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||||||||||
| // completeSubtreeIndexes splits [start, end) into the largest power-of-two | ||||||||||
| // subtrees the tree already keeps a single stored hash for, and appends each | ||||||||||
| // one's stored hash index left to right. | ||||||||||
| func completeSubtreeIndexes(start, end int64) []int64 { | ||||||||||
| level, ok := completeSubtree(start, end) | ||||||||||
| if ok { | ||||||||||
| return []int64{tlog.StoredHashIndex(level, start>>level)} | ||||||||||
| } | ||||||||||
| // completeSubtree accepts single leaves, and the input is always a valid | ||||||||||
| // subtree (end > start), so end-start >= 2 here. | ||||||||||
| mid := splitPoint(start, end) | ||||||||||
| return append(completeSubtreeIndexes(start, mid), completeSubtreeIndexes(mid, end)...) | ||||||||||
| } | ||||||||||
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||||||||||
| // hashSubtree returns the hash of the subtree [start, end), MTH(D[start:end]) | ||||||||||
| // from RFC 9162 section 2.1.1. It splits [start, end) into the largest | ||||||||||
| // power-of-two subtrees the tree already keeps a single stored hash for, reads | ||||||||||
| // those hashes through the provided reader in a single ReadHashes call, and | ||||||||||
| // combines them. | ||||||||||
| func hashSubtree(start, end int64, reader tlog.HashReader) (tlog.Hash, error) { | ||||||||||
| indexes := completeSubtreeIndexes(start, end) | ||||||||||
| hashes, err := reader.ReadHashes(indexes) | ||||||||||
| if err != nil { | ||||||||||
| return tlog.Hash{}, err | ||||||||||
| } | ||||||||||
| if len(hashes) != len(indexes) { | ||||||||||
| // Reader returned a slice shorter or larger than the requested indexes. | ||||||||||
| // Avoid panicking when we combine them. | ||||||||||
| return tlog.Hash{}, fmt.Errorf("ReadHashes returned %d hashes for %d indexes", len(hashes), len(indexes)) | ||||||||||
| } | ||||||||||
| h, _ := combineSubtreeRoots(start, end, hashes) | ||||||||||
| return h, nil | ||||||||||
| } | ||||||||||
|
|
||||||||||
| // subtreeSubProof implements the draft's SUBTREE_SUBPROOF from section 4.4.1 | ||||||||||
| // Generating a Subtree Consistency Proof (Appendix B.4), with the target | ||||||||||
| // subtree [start, end) and the node [windowStart, windowEnd) it sits in given | ||||||||||
| // as absolute leaf positions. known is the draft's b flag. It reads stored | ||||||||||
| // hashes through the provided reader and returns proof with the hashes it emits | ||||||||||
| // appended. | ||||||||||
| func subtreeSubProof(start, end, windowStart, windowEnd int64, known bool, reader tlog.HashReader, proof []tlog.Hash) ([]tlog.Hash, error) { | ||||||||||
| if start == windowStart && end == windowEnd { | ||||||||||
| // [start, end) covers the whole node, the SUBTREE_SUBPROOF base case. | ||||||||||
| // known decides whether the proof carries it. | ||||||||||
| if known { | ||||||||||
| // The verifier already has this node, so emit nothing. | ||||||||||
| return proof, nil | ||||||||||
| } | ||||||||||
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||||||||||
| // The verifier doesn't have it, so emit the node's hash. | ||||||||||
| h, err := hashSubtree(windowStart, windowEnd, reader) | ||||||||||
| if err != nil { | ||||||||||
| return nil, err | ||||||||||
| } | ||||||||||
| return append(proof, h), nil | ||||||||||
| } | ||||||||||
|
|
||||||||||
| // [start, end) covers only part of the node, so split the node at splitPoint. | ||||||||||
| // The switch routes by where the subtree falls (left child, right child, or | ||||||||||
| // straddle) and names the other child as the sibling the shared tail appends. | ||||||||||
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||||||||||
| // A one-leaf node has only itself as a subtree, which hits the base case | ||||||||||
| // above, so the node has >= 2 leaves here. | ||||||||||
| split := splitPoint(windowStart, windowEnd) | ||||||||||
| var err error | ||||||||||
| var siblingStart int64 | ||||||||||
| var siblingEnd int64 | ||||||||||
| switch { | ||||||||||
| case end <= split: | ||||||||||
| // The subtree is in the left child [windowStart, split). The right child | ||||||||||
| // is the sibling. | ||||||||||
| proof, err = subtreeSubProof(start, end, windowStart, split, known, reader, proof) | ||||||||||
| siblingStart = split | ||||||||||
| siblingEnd = windowEnd | ||||||||||
| case split <= start: | ||||||||||
| // The subtree is in the right child [split, windowEnd). The left child is | ||||||||||
| // the sibling. | ||||||||||
| proof, err = subtreeSubProof(start, end, split, windowEnd, known, reader, proof) | ||||||||||
| siblingStart = windowStart | ||||||||||
| siblingEnd = split | ||||||||||
| default: | ||||||||||
| // The subtree straddles the split (start < split < end), which a valid | ||||||||||
| // subtree only does when start == windowStart. Recurse into the right | ||||||||||
| // child, no longer a node the verifier knows (known = false). The left | ||||||||||
| // child is the sibling. | ||||||||||
| proof, err = subtreeSubProof(split, end, split, windowEnd, false, reader, proof) | ||||||||||
| siblingStart = windowStart | ||||||||||
| siblingEnd = split | ||||||||||
| } | ||||||||||
| if err != nil { | ||||||||||
| return nil, err | ||||||||||
| } | ||||||||||
| h, err := hashSubtree(siblingStart, siblingEnd, reader) | ||||||||||
| if err != nil { | ||||||||||
| return nil, err | ||||||||||
| } | ||||||||||
| return append(proof, h), nil | ||||||||||
| } | ||||||||||
|
|
||||||||||
| // ConsistencyProof returns SUBTREE_PROOF(start, end, D_n) for the tree of size | ||||||||||
| // treeSize, reading stored hashes through the provided reader, per the MTC | ||||||||||
| // draft section 4.4.1 Generating a Subtree Consistency Proof, detailed further | ||||||||||
| // in the draft's Appendix B.4. [start, end) must be a valid subtree with end <= | ||||||||||
| // treeSize. | ||||||||||
| // | ||||||||||
| // - https://ietf-plants-wg.github.io/merkle-tree-certs/draft-ietf-plants-merkle-tree-certs.html#section-4.4.1 | ||||||||||
| // - https://ietf-plants-wg.github.io/merkle-tree-certs/draft-ietf-plants-merkle-tree-certs.html#appendix-B.4 | ||||||||||
| func ConsistencyProof(start, end, treeSize int64, reader tlog.HashReader) ([]tlog.Hash, error) { | ||||||||||
| if !valid(start, end) || end > treeSize { | ||||||||||
| return nil, fmt.Errorf("[%d, %d) is not a valid subtree of a tree of size %d", start, end, treeSize) | ||||||||||
| } | ||||||||||
| return subtreeSubProof(start, end, 0, treeSize, true, reader, nil) | ||||||||||
| } | ||||||||||
|
|
||||||||||
| // VerifyConsistency reports whether proof shows that the subtree [start, end), | ||||||||||
| // whose hash is nodeHash, sits at those positions in the tree of size n with | ||||||||||
| // root rootHash. It follows the procedure in MTC draft section 4.4.3, detailed | ||||||||||
| // further in the draft's Appendix B.5. | ||||||||||
| // | ||||||||||
| // - https://ietf-plants-wg.github.io/merkle-tree-certs/draft-ietf-plants-merkle-tree-certs.html#section-4.4.3 | ||||||||||
| // - https://ietf-plants-wg.github.io/merkle-tree-certs/draft-ietf-plants-merkle-tree-certs.html#appendix-B.5 | ||||||||||
| func VerifyConsistency(start, end, n int64, proof []tlog.Hash, nodeHash, rootHash tlog.Hash) bool { | ||||||||||
| if !valid(start, end) || end > n { | ||||||||||
| return false | ||||||||||
| } | ||||||||||
|
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||||||||||
| // fn, sn, tn track the subtree's first leaf, its last leaf, and the tree's | ||||||||||
| // last leaf. Right-shifting a cursor climbs one level. | ||||||||||
| fn := start | ||||||||||
| sn := end - 1 | ||||||||||
| tn := n - 1 | ||||||||||
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||||||||||
| // Skip the levels that need no proof hash. The branch turns on whether the | ||||||||||
| // subtree's right edge meets the tree's right edge (sn == tn) or not. | ||||||||||
| if sn == tn { | ||||||||||
| // A flush subtree has no outside sibling to combine on the way up to | ||||||||||
| // nodeHash, so climb every level. | ||||||||||
|
Contributor
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more.
Suggested change
|
||||||||||
| for fn != sn { | ||||||||||
| fn >>= 1 | ||||||||||
| sn >>= 1 | ||||||||||
| tn >>= 1 | ||||||||||
| } | ||||||||||
| } else { | ||||||||||
| // An interior subtree eventually meets an outside sibling, so climb | ||||||||||
| // only while sn is a right child. | ||||||||||
| for fn != sn && sn&1 == 1 { | ||||||||||
| fn >>= 1 | ||||||||||
| sn >>= 1 | ||||||||||
| tn >>= 1 | ||||||||||
| } | ||||||||||
| } | ||||||||||
|
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||||||||||
| // fr and sr climb together from a shared seed: fr rebuilds the subtree | ||||||||||
| // hash, sr the tree root. | ||||||||||
|
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Contributor
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Nit:
Suggested change
(uses parallel terms, also more closely matches the description in 4.4.3) |
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| var fr tlog.Hash | ||||||||||
| var sr tlog.Hash | ||||||||||
| var rest []tlog.Hash | ||||||||||
| if fn == sn { | ||||||||||
| // A single node: the seed is its hash, nodeHash. | ||||||||||
| fr = nodeHash | ||||||||||
| sr = nodeHash | ||||||||||
| rest = proof | ||||||||||
| } else { | ||||||||||
| // The subtree is larger, so the seed is proof[0], the largest complete | ||||||||||
|
Contributor
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Larger than what? |
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| // subtree flush with its right edge. | ||||||||||
| if len(proof) == 0 { | ||||||||||
| return false | ||||||||||
| } | ||||||||||
| fr = proof[0] | ||||||||||
| sr = proof[0] | ||||||||||
| rest = proof[1:] | ||||||||||
| } | ||||||||||
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||||||||||
| for _, c := range rest { | ||||||||||
| if tn == 0 { | ||||||||||
| // The proof has more hashes than the tree has levels. | ||||||||||
| return false | ||||||||||
| } | ||||||||||
| if sn&1 == 1 || sn == tn { | ||||||||||
| if fn < sn { | ||||||||||
| // fr only combines while fn < sn. Freezing it at fn == sn is | ||||||||||
| // what makes the final fr == nodeHash check meaningful. | ||||||||||
|
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Contributor
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Optional:
Suggested change
Reasoning: I wasn't sure what "meaningful" meant in the second sentence. I've tried to give an explanation that made sense to me. Please let me know if you think it's correct! |
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| fr = tlog.NodeHash(c, fr) | ||||||||||
| } | ||||||||||
| sr = tlog.NodeHash(c, sr) | ||||||||||
| // At the ragged right edge (sn == tn) the just-combined node is | ||||||||||
| // shorter than its left sibling, so skip its empty levels here, | ||||||||||
| // consuming no proof hash, until sn is odd again. | ||||||||||
|
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Contributor
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. I don't understand this comment. Could you clarify? We could also drop it; the code matches the spec. |
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| for sn&1 == 0 { | ||||||||||
| fn >>= 1 | ||||||||||
| sn >>= 1 | ||||||||||
| tn >>= 1 | ||||||||||
| } | ||||||||||
| } else { | ||||||||||
| // c is the node's right sibling, outside the subtree, so it extends | ||||||||||
| // sr toward the root. | ||||||||||
| sr = tlog.NodeHash(sr, c) | ||||||||||
| } | ||||||||||
| fn >>= 1 | ||||||||||
| sn >>= 1 | ||||||||||
| tn >>= 1 | ||||||||||
| } | ||||||||||
| return tn == 0 && fr == nodeHash && sr == rootHash | ||||||||||
| } | ||||||||||
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I'm not sure what the last four words in this sentence mean - "the shared tail appends"?
Maybe this was meant to say something like: