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feat(linear_algebra/clifford_algebra/spin_group) : Spin Group #16040
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Note that the proofs of |
def invertible_of_invertible_ι (m : M) [invertible (ι Q m)] [invertible (2 : R)] : | ||
invertible (Q m) := sorry |
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Any more ideas on how to prove this or under what situations it's true?
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I already got the proof of this. I just need some time to tidy it up.
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Could you commit the messy version somewhere so that it doesn't get lost?
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Could you commit the messy version somewhere so that it doesn't get lost?
@Biiiilly Hi, I'm trying to make this PR work in Lean 4, do you still have the proof of this?
Co-authored-by: Jiale Miao <[email protected]>
Co-authored-by: Jiale Miao <[email protected]>
In this file we define
lipschitz
,pin_group
andspin_group
.Here are some discussion about the latent ambiguity of definition :
https://mathoverflow.net/q/427881/172242 and https://mathoverflow.net/q/251288/172242
The definition of the Lipschitz group
{𝑥 ∈ 𝐶𝑙(𝑉,𝑞) │ 𝑥 𝑖𝑠 𝑖𝑛𝑣𝑒𝑟𝑡𝑖𝑏𝑙𝑒 𝑎𝑛𝑑 𝑥𝑣𝑥⁻¹∈ 𝑉}
is given by:• Fulton, W. and Harris, J., 2004. Representation theory. New York: Springer, p.chapter 20.
• https://en.wikipedia.org/wiki/Clifford_algebra#Lipschitz_group
But they presumably form a group only in finite dimensions. So we define
lipschitz
with closure ofall the elements in the form of
ι Q m
. We show this definition is at least as large as theother definition (See
mem_lipschitz_conj_act_le
andmem_lipschitz_involute_le
) and the reversestatement presumably being true only in finite dimensions.
Note that the proofs of
mem_lipschitz_conj_act_le
andmem_lipschitz_involute_le
are blocked by some PRs shown below.invertible 2
]map_inv_of
and some other basic results #16202 [f (⅟r) = ⅟(f r)]