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guowenfeng committed May 28, 2021
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# Golang 为什么不能直接将任意类型数组赋值给 []interface{}

> 本篇参考: https://github.com/golang/go/wiki/InterfaceSlice
当我在写 go 代码时,想用 []interface{} 类型来接受一个任意类型的数组,从而进行泛型操作时,发现直接赋值会发生错误,导致 panic。

```go
dataSlice := []int{1, 2, 3, 4, 5, 6}
var interfaceSlice []interface{} = dataSlice
```

> Cannot use 'dataSlice' (type []int) as type []interface{}
IDE 会报以上错误。

原本我以为 interface{} 可以接收任何类型,[]interface{} 数组就应该可以接收任何类型的数组才对。

## Why?

先说结论:**[]interface{} 不是 interface{},它是一个元素类型为 interface{} 的切片。**

主要是因为 []interface{} 有特殊的内存布局。先看一下 interface{} 的内存布局:

![image-20210428153736553](/Users/guowenfeng/Library/Application Support/typora-user-images/image-20210428153736553.png)

如果是 []interface{} 就是 N 个上面的布局。可是普通类型的切片内存布局是:

![image-20210428155048225](/Users/guowenfeng/Library/Application Support/typora-user-images/image-20210428155048225.png)

所以,根本原因就是两个东西的内存布局不同,所以无法直接赋值。

## What can I do instead?

两种情况:

1. 你只是需要用一个容器去接收任意类型的切片,然后在进行索引之前就会将它转成原来的类型你只需要:

```go
var tmp interface{} = dataArr
```

2. 你的确需要将任意类型的数组转成 []interface{} ,然后去索引 []interface{} ,你只能遍历赋值:

```go
for index, data := range dataArr {
interfaceSlice = append(interfaceSlice, data)
// 这里可以直接在声明时就指定 []interface{} 的长度
// 用 interfaceSlice[index] = data 来代替会减少系统创建内存时消耗的时间
}
```

1 change: 1 addition & 0 deletions README.md
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# golang_daily_test
9 changes: 9 additions & 0 deletions go.mod
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module do_some_fxxking_test

go 1.14

require (
github.com/hashicorp/go-uuid v1.0.2 // indirect
golang.org/x/time v0.0.0-20210220033141-f8bda1e9f3ba // indirect
gopkg.in/eapache/queue.v1 v1.1.0 // indirect
)
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