[IMP] sync: display sync.job's state on sync order form

brain-tec · Mar 3, 2025 · 4591e6e · 4591e6e
1 parent 292fc99
commit 4591e6e
Show file tree

Hide file tree

Showing 2 changed files with 4 additions and 0 deletions.
diff --git a/sync/models/sync_order.py b/sync/models/sync_order.py
@@ -17,6 +17,9 @@ class SyncOrder(models.Model):
         required=True,
     )
     sync_job_id = fields.Many2one("sync.job")
+    sync_job_state = fields.Selection(
+        related="sync_job_id.state", string="Sync Job State"
+    )
     description = fields.Html(related="sync_task_id.sync_order_description")
     line_ids = fields.One2many(
         "sync.order.line", "sync_order_id", string="Linked Records"

diff --git a/sync/views/sync_order_views.xml b/sync/views/sync_order_views.xml
@@ -59,6 +59,7 @@
                         </group>
                         <group>
                             <field name="sync_job_id" readonly="1" />
+                            <field name="sync_job_state" readonly="1" />
                         </group>
                     </group>
                     <notebook>