sort array of objects

Javascript/sortArrayOfObjects.js

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+//sort an array of objects by the values of the object’s properties.
+let employees = [
+    {
+        firstName: 'John',
+        lastName: 'Doe',
+        age: 27,
+        joinedDate: 'December 15, 2017'
+    },
+
+    {
+        firstName: 'Ana',
+        lastName: 'Rosy',
+        age: 25,
+        joinedDate: 'January 15, 2019'
+    },
+
+    {
+        firstName: 'Zion',
+        lastName: 'Albert',
+        age: 30,
+        joinedDate: 'February 15, 2011'
+    }
+];
+//sorts the employees array by ages in ascending order
+employees.sort((a, b) => {
+    return a.age - b.age;
+});
+//display the employess ,useing forEach()
+employees.forEach((e) => {
+    console.log(`${e.firstName} ${e.lastName} ${e.age}`);
+});
+
+employees.sort((a, b) => b.age - a.age);
+//To sort the employees by ages in descending order, you just need to reverse the order in the comparison function. 
+employees.forEach((e) => {
+    console.log(`${e.firstName} ${e.lastName} ${e.age}`);
+});
+
+//Sort an array of objects by strings
+employees.sort((a, b) => {
+    let fa = a.firstName.toLowerCase(),
+        fb = b.firstName.toLowerCase();
+
+    if (fa < fb) {
+        return -1;
+    }
+    if (fa > fb) {
+        return 1;
+    }
+    return 0;
+});
+employees.forEach((e) => {
+    console.log(`${e.firstName} ${e.lastName}`);
+});
+//Sort an array of objects by dates
+employees.sort((a, b) => {
+    let da = new Date(a.joinedDate),
+        db = new Date(b.joinedDate);
+    return da - db;
+});
+employees.forEach((e) => {
+    console.log(`${e.firstName} ${e.lastName} ${e.joinedDate}`);
+});
+
+