Added Level 2 Excercises solutions

Author: zac11

Level2/Ex_5.py

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+"""
+
+Write a program that accepts a sequence of whitespace separated words as input and prints the words after removing all
+duplicate words and sorting them alphanumerically.
+Suppose the following input is supplied to the program:
+hello world and practice makes perfect and hello world again
+Then, the output should be:
+again and hello makes perfect practice world
+
+"""
+
+string_input = input()
+words =[word for word in string_input.split(" ")]
+print(" ".join(sorted(list(set(words)))))
+
+
+"""
+Let's break it down now
+
+
+print(set(words))
+
+
+This will print a set of the words, with all the unique values
+
+print(list(set(words)))
+
+
+Create a list out of the values of words
+
+print(sorted(list(set(words))))
+
+
+This will sort the list
+
+print(" ".join(sorted(list(set(words)))))
+
+
+This is join the sorted list items with a whitespace
+
+
+For this input :
+
+I like to yawn and I also like to make a music and a car
+
+Now output will be :
+
+I a also and car like make music to yawn
+
+Notice that the uppercase I is sorted at first position
+"""
+

Level2/Ex_6.py

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+"""
+
+Write a program which accepts a sequence of comma separated 4 digit binary numbers as its input and then check
+whether they are divisible by 5 or not. The numbers that are divisible by 5 are to be printed in a
+comma separated sequence.
+
+Example:
+0100,0011,1010,1001
+Then the output should be:
+1010
+"""
+string_val =input()
+val =[]
+
+items =[x for x in string_val.split(',')]
+
+for p in items:
+    div5 = int(p,2)    #converts the binary to a decimal
+    if not div5%5:
+        val.append(p)
+
+
+print(','.join(val))

Level2/Ex_7.py

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+"""
+
+Question:
+Write a program, which will find all such numbers between 1000 and 3000 (both included) such that each
+digit of the number is an even number.
+The numbers obtained should be printed in a comma-separated sequence on a single line.
+
+"""
+
+values =[]
+for i in range(1000,3001):
+    string_s = str(i)
+    if (int(string_s[0]) % 2 == 0) and (int(string_s[1]) % 2 == 0) \
+            and (int(string_s[2]) % 2 == 0) and (int(string_s[3]) % 2 == 0):
+        values.append(string_s)
+
+print(','.join(values))
+
+"""
+Output :
+2000,2002,2004,2006,2008,2020,2022,2024,2026,2028,2040,2042,2044,2046,2048,2060,2062,2064,
+2066,2068,2080,2082,2084,2086,2088,2200,2202,2204,2206,2208,2220,2222,2224,2226,2228,2240,
+2242,2244,2246,2248,2260,2262,2264,2266,2268,2280,2282,2284,2286,2288,2400,2402,2404,2406,
+2408,2420,2422,2424,2426,2428,2440,2442,2444,2446,2448,2460,2462,2464,2466,2468,2480,2482,
+2484,2486,2488,2600,2602,2604,2606,2608,2620,2622,2624,2626,2628,2640,2642,2644,2646,2648,
+2660,2662,2664,2666,2668,2680,2682,2684,2686,2688,2800,2802,2804,2806,2808,2820,2822,2824,
+2826,2828,2840,2842,2844,2846,2848,2860,2862,2864,2866,2868,2880,2882,2884,2886,2888
+"""

Level2/Ex_8.py

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+"""
+
+Write a program that accepts a sentence and calculate the number of letters and digits.
+Suppose the following input is supplied to the program:
+hello world! 123
+Then, the output should be:
+LETTERS 10
+DIGITS 3
+
+"""
+
+input_string = input()
+dict_d ={'DIGITS':0,'LETTERS':0}
+
+for items in input_string:
+    if items.isdigit():
+        dict_d['DIGITS']+=1
+    elif items.isalpha():
+        dict_d['LETTERS']+=1
+    else:
+        pass
+
+print('LETTERS are ',dict_d['LETTERS'])
+print('DIGITS are ', dict_d['DIGITS'])
+
+
+"""
+
+Harambe is dead. Please shout 12#4
+
+Output is :
+LETTERS are  24
+DIGITS are  3
+
+"""
+
+