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Copy pathMinimum_remove_to_make_valid_parentheses.py
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Minimum_remove_to_make_valid_parentheses.py
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"""
Given a string s of '(' , ')' and lowercase English characters.
Your task is to remove the minimum number of parentheses ( '(' or ')', in any positions ) so that the resulting parentheses string is valid and return any valid string.
Formally, a parentheses string is valid if and only if:
It is the empty string, contains only lowercase characters, or
It can be written as AB (A concatenated with B), where A and B are valid strings, or
It can be written as (A), where A is a valid string.
Example 1:
Input: s = "lee(t(c)o)de)"
Output: "lee(t(c)o)de"
Explanation: "lee(t(co)de)" , "lee(t(c)ode)" would also be accepted.
Example 2:
Input: s = "a)b(c)d"
Output: "ab(c)d"
Example 3:
Input: s = "))(("
Output: ""
Explanation: An empty string is also valid.
Constraints:
1 <= s.length <= 105
s[i] is either '(' , ')', or lowercase English letter.
"""
class Solution:
def minRemoveToMakeValid(self, s: str) -> str:
stack = []
for i, char in enumerate(s):
if char =='(':
stack.append(i)
elif char ==')':
if stack and s[stack[-1]] == '(':
stack.pop()
else:
stack.append(i)
result = []
for i, char in enumerate(s):
if stack and i == stack[0]:
stack.pop(0)
continue
result.append(char)
return ''.join(result)