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GCDs and Bezout's theorem #3
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I created a file called gcd.idr, where i put a proof of divisibility. Can someone please check it once. Thank You. |
It is better to just use a dependent pair like the one in lectures/homework
for being even, so one gets the factor directly.
…On Thu, Jan 24, 2019 at 11:55 AM NabarunDeka ***@***.***> wrote:
I created a file called gcd.idr, where i put a proof of divisibility. Can
someone please check it once. Thank You.
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I have added a Sigma-type for defining divisibility in |
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Euclid's algorithm extending to Bezout's lemma gives for natural numbers
a
andb
d
d
dividesa
andd
dividesb
k
andl
withd = a k + b l
As a consequence, we also have that if
c
divides botha
andb
, then it dividesd
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