added homework

isPrime.js

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+var isPrime = function(n){
+	if (n === 1) {return false;}
+	else if (n === 2) { return true;}
+	else if (n === 3) { return true;}
+	else {
+		for(var i = Math.floor(Math.sqrt(n)); i>=2; i--){
+			if(n%i ==0 || n%2 == 0 || n%3 == 0) {return false;}
+		}
+	}
+	return true;
+};
+
+console.log(isPrime(7));

letterCount.js

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+/** Write a function that takes a string that finds out how many times
+ a character occurs. For example, the string "apple" would print the 
+ following:
+
+a - 1
+p - 2
+l - 1
+e - 1
+BONUS: Make sure that lower case letters and upper case letters count for
+ the same character. Also, ignore spaces and punctuation. 
+
+ Notes: strings can be accessed like arrays (but you cant change them 
+ 	that way b/c all strings are constant)
+
+using objects here makes sense because want to associate a value (the letter) with
+its key (the count that the letter occurs)
+
+if (character in letterCount) {letterCount[character]+=1}else{
+	letterCount[character] = 1
+}
+**/
+
+var letterCount = function(str) {
+	var obj = {};
+	for (var i = 0; i<str.length; i+=1){
+		var letter = str[i];
+		if(letter in obj) {
+			obj[letter] += 1;
+		}
+		else {
+			obj[letter]=1; // here is where a letter is initially added to the object as a key and 1 is put in as the value
+		}
+	}
+	return obj;
+};
+
+console.log(letterCount("hello,world"));

numSquare.js

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+
+var numSquare = function(maxNum){
+	var perSquare = [];
+	for(var i=0; (i*i)<maxNum; i++) {
+		perSquare.push(i*i)
+	};
+return perSquare;
+}
+
+console.log(numSquare(100));

sillySum.js

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+var array = [1,2,3,45];
+
+
+var sillySum = function(taco){
+	var count = 0;
+	for (var i=0; i<taco.length; i++) {
+	count = count + (taco[i] * i);
+}
+return(count);
+}
+console.log(sillySum(array));