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1282-group-the-people-given-the-group-size-they-belong-to/README.md

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+<h2><a href="https://leetcode.com/problems/group-the-people-given-the-group-size-they-belong-to/">1282. Group the People Given the Group Size They Belong To</a></h2><h3>Medium</h3><hr><div><p>There are <code>n</code> people&nbsp;that are split into some unknown number of groups. Each person is labeled with a&nbsp;<strong>unique ID</strong>&nbsp;from&nbsp;<code>0</code>&nbsp;to&nbsp;<code>n - 1</code>.</p>
+
+<p>You are given an integer array&nbsp;<code>groupSizes</code>, where <code>groupSizes[i]</code>&nbsp;is the size of the group that person&nbsp;<code>i</code>&nbsp;is in. For example, if&nbsp;<code>groupSizes[1] = 3</code>, then&nbsp;person&nbsp;<code>1</code>&nbsp;must be in a&nbsp;group of size&nbsp;<code>3</code>.</p>
+
+<p>Return&nbsp;<em>a list of groups&nbsp;such that&nbsp;each person&nbsp;<code>i</code>&nbsp;is in a group of size&nbsp;<code>groupSizes[i]</code></em>.</p>
+
+<p>Each person should&nbsp;appear in&nbsp;<strong>exactly one group</strong>,&nbsp;and every person must be in a group. If there are&nbsp;multiple answers, <strong>return any of them</strong>. It is <strong>guaranteed</strong> that there will be <strong>at least one</strong> valid solution for the given input.</p>
+
+<p>&nbsp;</p>
+<p><strong>Example 1:</strong></p>
+
+<pre><strong>Input:</strong> groupSizes = [3,3,3,3,3,1,3]
+<strong>Output:</strong> [[5],[0,1,2],[3,4,6]]
+<b>Explanation:</b> 
+The first group is [5]. The size is 1, and groupSizes[5] = 1.
+The second group is [0,1,2]. The size is 3, and groupSizes[0] = groupSizes[1] = groupSizes[2] = 3.
+The third group is [3,4,6]. The size is 3, and groupSizes[3] = groupSizes[4] = groupSizes[6] = 3.
+Other possible solutions are [[2,1,6],[5],[0,4,3]] and [[5],[0,6,2],[4,3,1]].
+</pre>
+
+<p><strong>Example 2:</strong></p>
+
+<pre><strong>Input:</strong> groupSizes = [2,1,3,3,3,2]
+<strong>Output:</strong> [[1],[0,5],[2,3,4]]
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>groupSizes.length == n</code></li>
+	<li><code>1 &lt;= n&nbsp;&lt;= 500</code></li>
+	<li><code>1 &lt;=&nbsp;groupSizes[i] &lt;= n</code></li>
+</ul>
+</div>