Fix type parameter of applyWithFunction (#2396)

Type of `options` should not be used to infer type parameter `T`.
Refs: microsoft/TypeScript#14829

Author: ajafff

src/language/rule/abstractRule.ts

@@ -49,8 +49,16 @@ export abstract class AbstractRule implements IRule {
     }
 
     protected applyWithFunction(sourceFile: ts.SourceFile, walkFn: (ctx: WalkContext<void>) => void): RuleFailure[];
-    protected applyWithFunction<T>(sourceFile: ts.SourceFile, walkFn: (ctx: WalkContext<T>) => void, options: T): RuleFailure[];
-    protected applyWithFunction<T>(sourceFile: ts.SourceFile, walkFn: (ctx: WalkContext<T | void>) => void, options?: T): RuleFailure[] {
+    protected applyWithFunction<T, U extends T>(
+        sourceFile: ts.SourceFile,
+        walkFn: (ctx: WalkContext<T>) => void,
+        options: U,
+    ): RuleFailure[];
+    protected applyWithFunction<T, U extends T>(
+        sourceFile: ts.SourceFile,
+        walkFn: (ctx: WalkContext<T | void>) => void,
+        options?: U,
+    ): RuleFailure[] {
         const ctx = new WalkContext(sourceFile, this.ruleName, options);
         walkFn(ctx);
         return this.filterFailures(ctx.failures);