|
| 1 | +/* |
| 2 | +Technique used: |
| 3 | +
|
| 4 | +This method of detecting cycle is dependent upon Floyd's Cycle Detection Algorithm. |
| 5 | +In Floyd's Cycle Detection Algorithm, we take two pointers : fast and slow. |
| 6 | +The algorithm comes to an end when both of these pointers meet at a common point. |
| 7 | +Then, we store the address of the common point in a pointer variable (temp here). |
| 8 | +We start form the head of the linked list, and check each node if it is reachable |
| 9 | +from temp. That particular node, if found, is the starting node of the linked list. |
| 10 | +We assign a pointer to the previous one of this node. |
| 11 | +*/ |
| 12 | + |
| 13 | +#include<iostream> |
| 14 | +using namespace std; |
| 15 | + |
| 16 | +struct node |
| 17 | +{ |
| 18 | + int info; |
| 19 | + node *next; |
| 20 | +}; |
| 21 | + |
| 22 | +//creating a new node |
| 23 | +node *create (int x) |
| 24 | +{ |
| 25 | + node *ptr = new node; |
| 26 | + ptr->info = x; |
| 27 | + ptr->next = NULL; |
| 28 | + return ptr; |
| 29 | +} |
| 30 | + |
| 31 | +//printing the linked list |
| 32 | +void print (node * ptr) |
| 33 | +{ |
| 34 | + while (ptr != NULL) |
| 35 | + { |
| 36 | + cout << ptr->info << " "; |
| 37 | + ptr = ptr->next; |
| 38 | + } |
| 39 | + cout << "\n\n"; |
| 40 | +} |
| 41 | + |
| 42 | +//removing the cycle from the linked list |
| 43 | +void rem (node * slow_ptr, node * head) |
| 44 | +{ |
| 45 | + node *ptr; |
| 46 | + node *temp; |
| 47 | + ptr = head; |
| 48 | + while (1) |
| 49 | + { |
| 50 | + temp = slow_ptr; |
| 51 | + while (temp->next != slow_ptr && temp->next != ptr) |
| 52 | + { |
| 53 | + temp = temp->next; |
| 54 | + } |
| 55 | + if (temp->next == ptr) |
| 56 | + break; |
| 57 | + ptr = ptr->next; |
| 58 | + } |
| 59 | + temp->next = NULL; |
| 60 | +} |
| 61 | + |
| 62 | +//detecting cycle in the linked list |
| 63 | +int detect (node * ptr) |
| 64 | +{ |
| 65 | + node *slow_ptr = ptr; |
| 66 | + node *fast_ptr = ptr; |
| 67 | + while (slow_ptr && fast_ptr && fast_ptr->next) |
| 68 | + { |
| 69 | + slow_ptr = slow_ptr->next; |
| 70 | + fast_ptr = fast_ptr->next->next; |
| 71 | + if (slow_ptr == fast_ptr) |
| 72 | + { |
| 73 | + //remove function called |
| 74 | + rem (slow_ptr, ptr); |
| 75 | + return 1; |
| 76 | + } |
| 77 | + } |
| 78 | + return 0; |
| 79 | +} |
| 80 | + |
| 81 | +int main () |
| 82 | +{ |
| 83 | + node *head = create (10); |
| 84 | + head->next = create (20); |
| 85 | + head->next->next = create (30); |
| 86 | + head->next->next->next = head; |
| 87 | + //detect function called |
| 88 | + if (detect (head) == 1) |
| 89 | + { |
| 90 | + cout << "\nA cycle is present in the linked list\n"; |
| 91 | + cout << "\n\nAfter removing the cycle, linked list is as follows:\n"; |
| 92 | + //print function called |
| 93 | + print (head); |
| 94 | + } |
| 95 | + else |
| 96 | + cout << "No cycle is present within the loop\n"; |
| 97 | + return 0; |
| 98 | +} |
| 99 | + |
| 100 | +/* Sample input :HARDCORED VALUES: |
| 101 | + 10->20->30->(attached to head) |
| 102 | +
|
| 103 | + Sample output: |
| 104 | + A cycle is present in the linked list |
| 105 | +
|
| 106 | + After removing the cycle, linked list is as follows: |
| 107 | + 10 20 30 |
| 108 | +/* |
0 commit comments