compound literals

Author: ivanbrennan

prog.9.4A.c

@@ -0,0 +1,81 @@
+// Program to determine tomorrow's date
+
+#include <stdio.h>
+#include <stdbool.h>
+
+struct date
+{
+	int month;
+	int day;
+	int year;
+};
+
+// Function to calculate tomorrow's date
+
+struct date dateUpdate (struct date today)
+{
+	struct date tomorrow;
+	int numberOfDays (struct date d);
+
+	if ( today.day != numberOfDays (today) ) {
+		tomorrow = (struct date) { today.month, today.day + 1, today.year };
+	}
+	else if ( today.month == 12 ) {		// end of year
+		tomorrow = (struct date) { 1, 1, today.year + 1 };
+	}
+	else {								// end of month
+		tomorrow = (struct date) { 1, today.month + 1, today.year };
+	}
+
+	return tomorrow;
+}
+
+// Function to find the number of days in a month
+
+int numberOfDays (struct date d)
+{
+	int		days;
+	bool	isLeapYear (struct date d);
+
+	const int daysPerMonth[12] = {
+		31, 28, 31, 30, 31, 30,
+		31, 31, 30, 31, 30, 31
+	};
+
+	if ( isLeapYear (d) == true && d.month == 2 )
+		days = 29;
+	else
+		days = daysPerMonth[d.month - 1];
+
+	return days;
+}
+
+// Function to determine if it's a leap year
+
+bool isLeapYear (struct date d)
+{
+	bool leapYearFlag;
+
+	if ( (d.year % 4 == 0 && d.year % 100 != 0) || d.year % 400 == 0 )
+		leapYearFlag = true;	// It's a leap year
+	else
+		leapYearFlag = false;	// Not a leap year
+
+	return leapYearFlag;
+}
+
+int main (void)
+{
+	struct date dateUpdate (struct date today);
+	struct date thisDay, nextDay;
+
+	printf ("Enter today's date (mm dd yyyy): ");
+	scanf  ("%i%i%i", &thisDay.month, &thisDay.day, &thisDay.year);
+
+	nextDay = dateUpdate (thisDay);
+
+	printf ("Tomorrow's date is %i/%i/%.2i.\n", nextDay.month,
+			nextDay.day, nextDay.year % 100);
+
+	return 0;
+}