prog.9.2.c

// Program to determine tomorrow's date

#include <stdio.h>

int main (void)
{
	struct date
	{
		int month;
		int day;
		int year;
	};

	struct date today, tomorrow;

	const int daysPerMonth[12] = {
		31, 28, 31, 30, 31, 30,
		31, 31, 30, 31, 30, 31
	};

	printf ("Enter today's date (mm dd yyyy): ");
	scanf  ("%i%i%i", &today.month, &today.day, &today.year);

	if ( today.day != daysPerMonth[today.month - 1] ) {
		tomorrow.day = today.day + 1;
		tomorrow.month = today.month;
		tomorrow.year = today.year;
	}
	else if ( today.month == 12 ) {		// end of year
		tomorrow.day = 1;
		tomorrow.month = 1;
		tomorrow.year = today.year + 1;
	}
	else {								// end of month
		tomorrow.day = 1;
		tomorrow.month = today.month + 1;
		tomorrow.year = today.year;
	}

	printf ("Tomorrow's date is %i/%i/%.2i.\n", tomorrow.month,
			tomorrow.day, tomorrow.year % 100);

	return 0;
}