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| 1 | +function possiblyEquals(s1, s2) { |
| 2 | + const n = s1.length, m = s2.length; |
| 3 | + const dp = Array.from({ length: n + 1 }, v => Array.from({ length: m + 1}, w => new Set())); |
| 4 | + dp[0][0].add(0); |
| 5 | + |
| 6 | + for (let i = 0; i <= n; i++) { |
| 7 | + for (let j = 0; j <= m; j++) { |
| 8 | + for (let delta of dp[i][j]) { |
| 9 | + // s1 is number |
| 10 | + let num = 0; |
| 11 | + if (delta <= 0) { |
| 12 | + for (let p = i; i < Math.min(i + 3, n); p++) { |
| 13 | + if (isDigit(s1[p])) { |
| 14 | + num = num * 10 + Number(s1[p]); |
| 15 | + dp[p + 1][j].add(delta + num); |
| 16 | + } else { |
| 17 | + break; |
| 18 | + } |
| 19 | + } |
| 20 | + } |
| 21 | + |
| 22 | + // s2 is number |
| 23 | + num = 0; |
| 24 | + if (delta >= 0) { |
| 25 | + for (let q = j; q < Math.min(j + 3, m); q++) { |
| 26 | + if (isDigit(s2[q])) { |
| 27 | + num = num * 10 + Number(s2[q]); |
| 28 | + dp[i][q + 1].add(delta - num); |
| 29 | + } else { |
| 30 | + break; |
| 31 | + } |
| 32 | + } |
| 33 | + } |
| 34 | + |
| 35 | + // match s1 non-digit character |
| 36 | + if (i < n && delta < 0 && !isDigit(s1[i])) { |
| 37 | + dp[i + 1][j].add(delta + 1); |
| 38 | + } |
| 39 | + |
| 40 | + // match s2 non-digit character |
| 41 | + if (j < m && delta > 0 && !isDigit(s2[j])) { |
| 42 | + dp[i][j + 1].add(delta - 1); |
| 43 | + } |
| 44 | + |
| 45 | + // two non-digit character match |
| 46 | + if (i < n && j < m && delta == 0 && s1[i] == s2[j]) { |
| 47 | + dp[i + 1][j + 1].add(0); |
| 48 | + } |
| 49 | + |
| 50 | + } |
| 51 | + } |
| 52 | + } |
| 53 | + return dp[n][m].has(0); |
| 54 | +}; |
| 55 | + |
| 56 | +function isDigit(char) { |
| 57 | + return (/^\d{1}$/g).test(char); |
| 58 | +} |
| 59 | + |
| 60 | +// another |
| 61 | + |
1 | 62 | /**
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2 | 63 | * @param {string} s1
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3 | 64 | * @param {string} s2
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