Update 438-find-all-anagrams-in-a-string.js

Author: everthis

438-find-all-anagrams-in-a-string.js

@@ -3,34 +3,26 @@
  * @param {string} p
  * @return {number[]}
  */
-const findAnagrams = function(s, p) {
-    const slen = s.length
-    const plen = p.length
-    if( plen > slen ) {
-        return []
+const findAnagrams = function (s, p) {
+  const slen = s.length;
+  const plen = p.length;
+  if (plen > slen) return [];
+  const aCode = "a".charCodeAt(0);
+  const count = new Array(26).fill(0);
+  for (let i = 0; i < plen; i++) count[p.charCodeAt(i) - aCode] += 1;
+  const res = [];
+  for (let i = 0; i < slen; i++) {
+    count[s.charCodeAt(i) - aCode] -= 1;
+    if (i >= plen - 1) {
+      if (i - plen >= 0) count[s.charCodeAt(i - plen) - aCode] += 1;
+      if (allZero(count)) res.push(i - plen + 1);
     }
-    const aCode = ('a').charCodeAt(0)
-    const count = new Array(26).fill(0)
-    for(let i = 0; i < plen; i++) {
-        count[ p.charCodeAt(i) - aCode ] += 1
-    }
-    const res = []
-    for(let i = 0; i < slen; i++) {
-        count[ s.charCodeAt(i) - aCode ] -= 1
-        if (i >= plen - 1) {
-            if(i - plen >= 0) count[ s.charCodeAt( i - plen ) - aCode ] += 1
-            if (allZero(count)) {
-                res.push(i - plen + 1)
-            }
-        }
-    }
-
-    return res
+  }
+  return res;
 };
-
 function allZero(count) {
-    for(let el of count) {
-        if(el !== 0) return false
-    }
-    return true
+  for (let el of count) {
+    if (el !== 0) return false;
+  }
+  return true;
 }