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| 1 | +/** |
| 2 | + * Definition for a binary tree node. |
| 3 | + * function TreeNode(val, left, right) { |
| 4 | + * this.val = (val===undefined ? 0 : val) |
| 5 | + * this.left = (left===undefined ? null : left) |
| 6 | + * this.right = (right===undefined ? null : right) |
| 7 | + * } |
| 8 | + */ |
| 9 | +/** |
| 10 | + * @param {TreeNode} root |
| 11 | + * @param {number[]} queries |
| 12 | + * @return {number[]} |
| 13 | + */ |
| 14 | +const treeQueries = function(root, queries) { |
| 15 | + const height = [], depth = [], { max } = Math |
| 16 | + dfs(root, 0) |
| 17 | + |
| 18 | + function dfs(node, dep) { |
| 19 | + if(node == null) return 0 |
| 20 | + depth[node.val] = dep |
| 21 | + const h = max(dfs(node.left, dep + 1), dfs(node.right, dep + 1)) |
| 22 | + height[node.val] = h |
| 23 | + return h + 1 |
| 24 | + } |
| 25 | + // console.log(height, depth) |
| 26 | + |
| 27 | + const neighbors = [] |
| 28 | + for(let i = 1; i < height.length; i++) { |
| 29 | + if(height[i] == null) continue |
| 30 | + const d = depth[i] |
| 31 | + if(neighbors[d] == null) neighbors[d] = [] |
| 32 | + neighbors[d].push([height[i], i]) |
| 33 | + neighbors[d].sort((a, b) => b[0] - a[0]) |
| 34 | + if(neighbors[d].length > 2) neighbors[d].pop() |
| 35 | + } |
| 36 | + // console.log(neighbors) |
| 37 | + const res = [] |
| 38 | + for(const q of queries) { |
| 39 | + const d = depth[q] |
| 40 | + if(neighbors[d].length === 1) res.push(d - 1) |
| 41 | + else if(q === neighbors[d][0][1]) { |
| 42 | + // console.log('in', d) |
| 43 | + res.push(d + neighbors[d][1][0]) |
| 44 | + } else { |
| 45 | + res.push(d + neighbors[d][0][0]) |
| 46 | + } |
| 47 | + } |
| 48 | + |
| 49 | + return res |
| 50 | +}; |
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