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Create 985-sum-of-even-numbers-after-queries.js
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/**
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* @param {number[]} A
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* @param {number[][]} queries
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* @return {number[]}
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*/
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const sumEvenAfterQueries = function(A, queries) {
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const res = []
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for(let i = 0; i < queries.length; i++) {
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A[queries[i][1]] += queries[i][0]
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res.push(sum(A))
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}
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return res
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};
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function sum(arr) {
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return arr.reduce((ac, el) => ac + (el % 2 === 0 ? el : 0), 0)
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}
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// another, better
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const sumEvenAfterQueries = function(A, queries) {
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let sum = A.reduce((acc, cur) => cur%2 == 0 ? acc + cur : acc, 0);
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return queries.map((q) => {
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let i = q[1];
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let s = A[i] + q[0];
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if(s%2 === 0) {
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sum += q[0];
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if(A[i]%2 !== 0) sum += A[i];
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} else if(A[i]%2 === 0) sum -= A[i];
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A[i] = s;
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return sum;
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});
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};

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