128-longest-consecutive-sequence.js

/**
 * @param {number[]} nums
 * @return {number}
 */
const longestConsecutive = function(nums) {
  if(nums.length === 0) return 0
  nums.sort((a, b) => a - b)
  let max = 1
  let cur = 1
  for(let i = 1; i < nums.length; i++) {
    if(nums[i] - nums[i-1] === 1) {
       cur += 1
       max = Math.max(max, cur)
    } else if(nums[i] - nums[i-1] === 0) {
              
    } else {
      cur = 1
    }
  }
  
  return max
};