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Copy file name to clipboardexpand all lines: ADC/Part3/Section2.md
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@@ -27,7 +27,7 @@ You should have a basic understanding of the operation of this circuit from the
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As you have seen in the lectures, operating the amplifier at the correct biasing point is important: we need to get a high gain, and we need to avoid saturation of the BJT.
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Our general aim therefore is to place the quiescent operating point (i.e. when $V_\text{in}$ is open circuit) such that $V_\mathrm{C} = V_\mathrm{CC}/2$.
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Using a single rail supply ($V_\text{CC}=5$V and connecting emitter node E to GND), we can bias the output of the amplifier at a quiescent voltage of about 2.5V.
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Using a single rail supply ($V_\text{CC}$=5V and connecting emitter node E to GND), we can bias the output of the amplifier at a quiescent voltage of about 2.5V.
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Thus 2.5V will be dropped across resistor $R_\text{C}$, so chose \$R_\text{C}$=10kΩ to get 0.25mA of quiescent collector bias current.
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Given the values of $R_\text{B1}$ and $R_\text{B2}$, estimate an expected value for the potentiometer $R_\text{B3}$ to bias your CE amplifier around a quiescent output voltage of 2.5V.
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