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/*
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Intersection of Two Linked Lists
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================================
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Write a program to find the node at which the intersection of two singly linked lists begins.
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Example 1:
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Input: intersectVal = 8, listA = [4,1,8,4,5], listB = [5,6,1,8,4,5], skipA = 2, skipB = 3
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Output: Reference of the node with value = 8
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Input Explanation: The intersected node's value is 8 (note that this must not be 0 if the two lists intersect). From the head of A, it reads as [4,1,8,4,5]. From the head of B, it reads as [5,6,1,8,4,5]. There are 2 nodes before the intersected node in A; There are 3 nodes before the intersected node in B.
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Example 2:
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Input: intersectVal = 2, listA = [1,9,1,2,4], listB = [3,2,4], skipA = 3, skipB = 1
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Output: Reference of the node with value = 2
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Input Explanation: The intersected node's value is 2 (note that this must not be 0 if the two lists intersect). From the head of A, it reads as [1,9,1,2,4]. From the head of B, it reads as [3,2,4]. There are 3 nodes before the intersected node in A; There are 1 node before the intersected node in B.
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Example 3:
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Input: intersectVal = 0, listA = [2,6,4], listB = [1,5], skipA = 3, skipB = 2
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Output: null
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Input Explanation: From the head of A, it reads as [2,6,4]. From the head of B, it reads as [1,5]. Since the two lists do not intersect, intersectVal must be 0, while skipA and skipB can be arbitrary values.
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Explanation: The two lists do not intersect, so return null.
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Notes:
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If the two linked lists have no intersection at all, return null.
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The linked lists must retain their original structure after the function returns.
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You may assume there are no cycles anywhere in the entire linked structure.
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Each value on each linked list is in the range [1, 10^9].
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Your code should preferably run in O(n) time and use only O(1) memory.
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*/
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/**
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* Definition for singly-linked list.
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* struct ListNode {
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* int val;
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* ListNode *next;
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* ListNode(int x) : val(x), next(NULL) {}
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* };
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*/
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class Solution
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{
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public:
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ListNode *getIntersectionNode(ListNode *headA, ListNode *headB)
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{
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int sizeA = 0, sizeB = 0;
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auto tempA = headA, tempB = headB;
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while (tempA)
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{
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sizeA++;
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tempA = tempA->next;
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}
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while (tempB)
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{
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sizeB++;
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tempB = tempB->next;
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}
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tempA = headA;
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tempB = headB;
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while (sizeA > sizeB)
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{
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tempA = tempA->next;
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sizeA--;
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}
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while (sizeB > sizeA)
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{
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tempB = tempB->next;
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sizeB--;
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}
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while (tempA != tempB)
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{
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tempA = tempA->next;
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tempB = tempB->next;
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}
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return tempA;
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}
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};

Leetcode Daily Challenge/March-2021/README.md

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| 1. | [Distribute Candies](https://leetcode.com/explore/challenge/card/march-leetcoding-challenge-2021/588/week-1-march-1st-march-7th/3657/) | [cpp](./01.%20Distribute%20Candies.cpp) |
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| 2. | [Set Mismatch](https://leetcode.com/explore/challenge/card/march-leetcoding-challenge-2021/588/week-1-march-1st-march-7th/3658/) | [cpp](./02.%20Set%20Mismatch.cpp) |
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| 3. | [Missing Number](https://leetcode.com/explore/challenge/card/march-leetcoding-challenge-2021/588/week-1-march-1st-march-7th/3659/) | [cpp](./03.%20Missing%20Number.cpp) |
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| 4. | [Intersection of Two Linked Lists](https://leetcode.com/explore/challenge/card/march-leetcoding-challenge-2021/588/week-1-march-1st-march-7th/3660/) | [cpp](./04.%20Intersection%20of%20Two%20Linked%20Lists.cpp) |

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