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| 1 | +/* |
| 2 | +You are given a Binary Tree of type integer, a target node, and an integer value K. |
| 3 | +Print the data of all nodes that have a distance K from the target node. The order in which they would be printed will not matter. |
| 4 | + |
| 5 | +Input Format: |
| 6 | +The first line of input will contain the node data, all separated by a single space. Since -1 is used as an indication whether the left or right node data exist for root, it will not be a part of the node data. |
| 7 | +The second line of input contains two integers separated by a single space, representing the value of the target node and K, respectively. |
| 8 | + |
| 9 | +Output Format: |
| 10 | +All the node data at distance K from the target node will be printed on a new line. |
| 11 | +The order in which the data is printed doesn't matter. |
| 12 | + |
| 13 | +Constraints: |
| 14 | +1 <= N <= 10^5 |
| 15 | +Where N is the total number of nodes in the binary tree. |
| 16 | +Time Limit: 1 sec |
| 17 | + |
| 18 | +Sample Input 1: |
| 19 | +5 6 10 2 3 -1 -1 -1 -1 -1 9 -1 -1 |
| 20 | +3 1 |
| 21 | +Sample Output 1: |
| 22 | +9 |
| 23 | +6 |
| 24 | + |
| 25 | +Sample Input 2: |
| 26 | +1 2 3 4 5 6 7 -1 -1 -1 -1 -1 -1 -1 -1 |
| 27 | +3 3 |
| 28 | +Sample Output 2: |
| 29 | +4 |
| 30 | +5 |
| 31 | +*/ |
| 32 | + |
| 33 | +/* |
| 34 | + |
| 35 | + Following is the structure used to represent the Binary Tree Node |
| 36 | + |
| 37 | + class BinaryTreeNode<T> { |
| 38 | + T data; |
| 39 | + BinaryTreeNode<T> left; |
| 40 | + BinaryTreeNode<T> right; |
| 41 | + |
| 42 | + public BinaryTreeNode(T data) { |
| 43 | + this.data = data; |
| 44 | + this.left = null; |
| 45 | + this.right = null; |
| 46 | + } |
| 47 | + } |
| 48 | + |
| 49 | +*/ |
| 50 | + |
| 51 | +public class Solution { |
| 52 | + |
| 53 | + public static void nodesAtDistanceK(BinaryTreeNode<Integer> root, int node, int k) { |
| 54 | + //Your code goes here |
| 55 | + print(root,node,k); |
| 56 | + |
| 57 | + |
| 58 | + } |
| 59 | + |
| 60 | + private static int print(BinaryTreeNode<Integer> root, int node, int k) |
| 61 | + { |
| 62 | + //If tree is empty return -1 |
| 63 | + if (root==null) |
| 64 | + return -1; |
| 65 | + |
| 66 | + int rootData=root.data; |
| 67 | + if (rootData==node) |
| 68 | + { |
| 69 | + printNodesAtDistanceK(root, k); |
| 70 | + return 0; |
| 71 | + } |
| 72 | + |
| 73 | + int leftSubTreeDist=0,rightSubTreeDist=0; |
| 74 | + |
| 75 | + leftSubTreeDist=print(root.left,node,k); |
| 76 | + if (leftSubTreeDist!=-1) |
| 77 | + { |
| 78 | + if(leftSubTreeDist+1==k) |
| 79 | + { |
| 80 | + System.out.println(rootData); |
| 81 | + } |
| 82 | + else |
| 83 | + { |
| 84 | + rightSubTreeDist=k-(leftSubTreeDist+1)-1; |
| 85 | + printNodesAtDistanceK(root.right, rightSubTreeDist); |
| 86 | + } |
| 87 | + return leftSubTreeDist+1; |
| 88 | + } |
| 89 | + |
| 90 | + rightSubTreeDist=print(root.right,node,k); |
| 91 | + if (rightSubTreeDist!=-1) |
| 92 | + { |
| 93 | + if(rightSubTreeDist+1==k) |
| 94 | + { |
| 95 | + System.out.println(rootData); |
| 96 | + } |
| 97 | + else |
| 98 | + { |
| 99 | + leftSubTreeDist=k-(rightSubTreeDist+1)-1; |
| 100 | + printNodesAtDistanceK(root.left, leftSubTreeDist); |
| 101 | + } |
| 102 | + return rightSubTreeDist+1; |
| 103 | + } |
| 104 | + return -1; |
| 105 | + } |
| 106 | + |
| 107 | + private static void printNodesAtDistanceK(BinaryTreeNode<Integer> root, int k) |
| 108 | + { |
| 109 | + if (root==null || k<0) |
| 110 | + return; |
| 111 | + |
| 112 | + if (k == 0) |
| 113 | + { |
| 114 | + System.out.println(root.data); |
| 115 | + return; |
| 116 | + } |
| 117 | + |
| 118 | + printNodesAtDistanceK(root.left,k-1); |
| 119 | + printNodesAtDistanceK(root.right,k-1); |
| 120 | + } |
| 121 | + |
| 122 | +} |
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