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| 1 | +package weekly; |
| 2 | + |
| 3 | +import java.util.ArrayList; |
| 4 | +import java.util.Arrays; |
| 5 | +import java.util.HashMap; |
| 6 | +import java.util.LinkedList; |
| 7 | +import java.util.List; |
| 8 | +import java.util.Map; |
| 9 | +import java.util.Queue; |
| 10 | + |
| 11 | +public class wk304 { |
| 12 | + |
| 13 | + //简单题,排序+模拟 |
| 14 | + //其实可以直接求不同数字个数 |
| 15 | + public int minimumOperations(int[] nums) { |
| 16 | + Arrays.sort(nums); |
| 17 | + int i = 0; |
| 18 | + int max = nums[nums.length - 1]; |
| 19 | + int sum = 0; |
| 20 | + int ans = 0; |
| 21 | + while (sum < max) { |
| 22 | + nums[i] -= sum; |
| 23 | + if (nums[i] <= 0) { |
| 24 | + i++; |
| 25 | + } else { |
| 26 | + sum += nums[i++]; |
| 27 | + ans++; |
| 28 | + } |
| 29 | + } |
| 30 | + |
| 31 | + return ans; |
| 32 | + |
| 33 | + } |
| 34 | + |
| 35 | + |
| 36 | + //中等题,排序后开始拿1 2 3 ...个 要注意追后的时候要判断能不能构成一个新的组 |
| 37 | + public int maximumGroups(int[] grades) { |
| 38 | + Arrays.sort(grades); |
| 39 | + int pre = 0; |
| 40 | + int count = 0; |
| 41 | + int i = 0; |
| 42 | + int ans = 0; |
| 43 | + for (i = 0; i < grades.length; ) { |
| 44 | + int pcount = 0; |
| 45 | + int psum = 0; |
| 46 | + while (i < grades.length && pcount <= count) { |
| 47 | + psum += grades[i++]; |
| 48 | + pcount++; |
| 49 | + } |
| 50 | + if (psum <= pre || pcount <= count) { |
| 51 | + return ans; |
| 52 | + } |
| 53 | + ans++; |
| 54 | + pre = psum; |
| 55 | + count = pcount; |
| 56 | + } |
| 57 | + return ans; |
| 58 | + } |
| 59 | + |
| 60 | + |
| 61 | + //中等题,图遍历就行了,找出每个点到所有点的距离 |
| 62 | + public int closestMeetingNode(int[] edges, int node1, int node2) { |
| 63 | + int[] dis1 = help(edges, node1); |
| 64 | + int[] dis2 = help(edges, node2); |
| 65 | + int ans = -1; |
| 66 | + int min = Integer.MAX_VALUE; |
| 67 | + for (int i = 0; i < dis1.length; i++) { |
| 68 | + if (dis1[i] == 0 || dis2[i] == 0) continue; |
| 69 | + int max = Math.max(dis1[i], dis2[i]); |
| 70 | + if (max < min) { |
| 71 | + ans = i; |
| 72 | + min = max; |
| 73 | + } |
| 74 | + } |
| 75 | + return ans; |
| 76 | + |
| 77 | + } |
| 78 | + |
| 79 | + int[] help(int[] edges, int node) { |
| 80 | + int[] dis = new int[edges.length]; |
| 81 | + int step = 0; |
| 82 | + //没路可走 或者 已经访问过 |
| 83 | + while (node != -1 && dis[node] == 0) { |
| 84 | + dis[node] = step; |
| 85 | + node = edges[node]; |
| 86 | + step++; |
| 87 | + } |
| 88 | + return dis; |
| 89 | + } |
| 90 | + /* int[] help(int[] edges, int node) { |
| 91 | + int[] dis = new int[edges.length]; |
| 92 | + Arrays.fill(dis, -1); |
| 93 | + boolean[] visited = new boolean[edges.length]; |
| 94 | + Queue<Integer> queue = new LinkedList<>(); |
| 95 | + queue.add(node); |
| 96 | + int step = 0; |
| 97 | + visited[node] = true; |
| 98 | + while (!queue.isEmpty()) { |
| 99 | + int size = queue.size(); |
| 100 | + while (size-- > 0) { |
| 101 | + Integer cur = queue.poll(); |
| 102 | + dis[cur] = step; |
| 103 | + int next = edges[cur]; |
| 104 | + if (next == -1 || visited[next]) continue; |
| 105 | + queue.add(next); |
| 106 | + visited[next] = true; |
| 107 | + } |
| 108 | + step++; |
| 109 | + } |
| 110 | + return dis; |
| 111 | + }*/ |
| 112 | + |
| 113 | + |
| 114 | + //困难题,周赛写的解法 |
| 115 | + /*public int longestCycle(int[] edges) { |
| 116 | + int[] in = new int[edges.length]; |
| 117 | + for (int i = 0; i < edges.length; i++) { |
| 118 | + if (edges[i] == -1) continue; |
| 119 | + in[edges[i]]++; |
| 120 | + } |
| 121 | +
|
| 122 | + int max = -1; |
| 123 | + boolean[] visited = new boolean[edges.length]; |
| 124 | + for (int i = 0; i < in.length; i++) { |
| 125 | + max = Math.max(max, help2(edges, visited, i)); |
| 126 | + } |
| 127 | + return max; |
| 128 | + } |
| 129 | +
|
| 130 | + int help2(int[] edges, boolean[] visited, int node) { |
| 131 | + List<Integer> path = new ArrayList<>(); |
| 132 | + while (!visited[node]) { |
| 133 | + path.add(node); |
| 134 | + visited[node] = true; |
| 135 | + node = edges[node]; |
| 136 | + if (node == -1) break; |
| 137 | + } |
| 138 | + if (node == -1) return -1; |
| 139 | + for (int i = 0; i < path.size(); i++) { |
| 140 | + if (path.get(i) == node) { |
| 141 | + return path.size() - i; |
| 142 | + } |
| 143 | + } |
| 144 | + return -1; |
| 145 | + }*/ |
| 146 | + |
| 147 | + |
| 148 | + //时间计时法,还可以拓扑排序删除不是坏的变,然后bfs求环长度 |
| 149 | + public int longestCycle(int[] edges) { |
| 150 | + int[] dis = new int[edges.length]; |
| 151 | + |
| 152 | + int ans = -1; |
| 153 | + int step = 1; |
| 154 | + for (int i = 0; i < edges.length; i++) { |
| 155 | + if (dis[i] == 0) { |
| 156 | + int start = step; |
| 157 | + int node = i; |
| 158 | + while (node != -1 && dis[node] == 0) { |
| 159 | + dis[node] = step++; |
| 160 | + node = edges[node]; |
| 161 | + } |
| 162 | + if (node != -1 && dis[node] >= start) { |
| 163 | + ans = Math.max(step - dis[node], ans); |
| 164 | + } |
| 165 | + } |
| 166 | + } |
| 167 | + return ans; |
| 168 | + |
| 169 | + } |
| 170 | + |
| 171 | + |
| 172 | + public static void main(String[] args) { |
| 173 | + wk304 w = new wk304(); |
| 174 | + w.longestCycle(new int[]{3, 3, 4, 2, 3}); |
| 175 | + } |
| 176 | +} |
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