Create 001.js

Author: Walker30263

001.js

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+/*
+Source: https://projecteuler.net/problem=1
+
+Problem:
+
+"If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
+
+Find the sum of all the multiples of 3 or 5 below 1000."
+
+
+My Algorithm in words:
+
+1. Define a variable to hold the sum
+2. Run a for-loop from 1 to 1000
+3. If the number is a multiple of 3 or 5, add the number to the sum variable
+4. Return the sum variable
+
+*/
+
+function solution() {
+  var sum = 0; 
+
+  for (let i = 0; i < 1000; i++) {
+    if ((i % 3 === 0) || (i % 5 === 0)) { //to check whether i is divisble by 3 or 5, we check the remainder (with mod) when i is divided by 3 or 5
+      sum += i;
+    }
+  }
+
+  return sum;
+}
+
+console.log(solution()) //outputs the answer!