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1901040027/1001S02E01_helloworld.txt

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# 自学 Python 训练营
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### 入门训练营
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#### 基本介绍
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> 所谓"自学",就是"自己一个人(默默地)学" —— 这恰恰是绝大多数人一生学习失败的最根本原因。
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训练营由 "新生大学" 联合 "糖果" 发起,针对基础相对薄弱,想要自学 Python 的人组织的训练营。
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训练营期间由 `教研组` 规划学习路线、提供学习素材,`学员` 通过阅读、实践、交流等方式自学为主,遇到确实无法完成的难题会有专业的 `编程教练` 帮助解答,`辅导员` 会在整个过程中鼓励、推动,帮助学员完成整个训练。
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#### 简单规则
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1. 训练营每期 50 人,每 10 人一小组,每小组配备一名 `编程教练` 和一名 `辅导员`,周期为 14 天。
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2. 训练营需缴纳保证金 + 服务费,具体定价会根据运营成本动态调整。
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3. 每天 00:00 会发布当天 `学习材料` 和 `自学任务`,学员需要在 24:00 前完成。
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4. 每天需要 `提交作业` 和 `学习总结打卡`,可获得 `星星`,通过积累 `星星` 到达合格标准以上,在结营时可全额返回保证金。
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5. 每期会有10个名额针对 "新生大学会员" 推荐的在校高中生和在校大学生免收服务费。
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[《自学 Python 入门训练营》报名入口](https://h5.youzan.com/v2/goods/2fo1zmvtzgvec)
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ssd

1901040027/README.md

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# 自学 Python 训练营
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### 入门训练营
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#### 基本介绍
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> 所谓"自学",就是"自己一个人(默默地)学" —— 这恰恰是绝大多数人一生学习失败的最根本原因。
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训练营由 "新生大学" 联合 "糖果" 发起,针对基础相对薄弱,想要自学 Python 的人组织的训练营。
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训练营期间由 `教研组` 规划学习路线、提供学习素材,`学员` 通过阅读、实践、交流等方式自学为主,遇到确实无法完成的难题会有专业的 `编程教练` 帮助解答,`辅导员` 会在整个过程中鼓励、推动,帮助学员完成整个训练。
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#### 简单规则
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1. 训练营每期 50 人,每 10 人一小组,每小组配备一名 `编程教练` 和一名 `辅导员`,周期为 14 天。
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2. 训练营需缴纳保证金 + 服务费,具体定价会根据运营成本动态调整。
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3. 每天 00:00 会发布当天 `学习材料``自学任务`,学员需要在 24:00 前完成。
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4. 每天需要 `提交作业``学习总结打卡`,可获得 `星星`,通过积累 `星星` 到达合格标准以上,在结营时可全额返回保证金。
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5. 每期会有10个名额针对 "新生大学会员" 推荐的在校高中生和在校大学生免收服务费。
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[《自学 Python 入门训练营》报名入口](https://h5.youzan.com/v2/goods/2fo1zmvtzgvec)
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ssd

19100101/Shawn/d12_training1.py

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import requests
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from pyquery import PyQuery
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from mymodule import stats_word
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# 通过url获取文本并分析
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def stats (url) :
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response = requests.get(url)
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# 提取微信公众号正文
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document = PyQuery (response.text)
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content = document ('#js_content').text()
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# 统计前100词频
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statList = stats_word.stats_text(content,100)
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statString = ''.join(str(i) for i in statList)
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return statString

19100101/Shawn/d12_training2.py

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from wxpy import *
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import d12_training1
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bot = Bot()
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# 找到好友并发消息
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my_friend = bot.friends().search('Somebody')[0]
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my_friend.send('请给我分享一篇文章')
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# 获取分享文章url
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@bot.register(my_friend)
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def get_msg (msg) :
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if msg.type == 'Sharing' :
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target_url = msg.url
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stats_msg = d12_training1.stats(target_url)
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my_friend.send(stats_msg)
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else :
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pass
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embed()

19100101/YanHuiii/d12_training2.py

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'''这是一个利用wxpy功能自动完成微信登录和获取好友转发的网址信息,
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将信息中的主要内容提取及获取词频反馈,并把结果发给好友的程序'''
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import training1
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from wxpy import *
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'''登录微信'''
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bot = Bot()
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object1 = bot.friends()
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@bot.register(object1)
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def SHARING_Msg (msg) :
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if msg.type == 'Sharing' :
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url = msg.url
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msg.reply(training1.stats_meg(url))
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else :
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print("您的好友还没发给您关于分享类型的信息")
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embed()
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19100101/YanHuiii/training1.py

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'''这是一个通过网络请求获得网页内容,使用分词工具对中文字符串
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进行分词,统计词频,返回结果'''
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import requests
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import pyquery
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from pyquery import PyQuery
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from mymodule import stats_word
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def stats_meg(url):
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'''获取网址'''
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image_url = url
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'''将网址中的内容全部赋值给response'''
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response = requests.get(image_url)
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'''提取网址中的正文内容'''
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document = pyquery.PyQuery(response.text)
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content = document('#js_content').text()
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'''返回网址正文中前100位的中文词频结果'''
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return stats_word.stats_text_cn(content,100)

19100101/lidong2119/d11_training1.py

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import requests
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import yagmail
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import getpass
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# import yagmail
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from pyquery import PyQuery
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from mymodule import stats_word
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image_url = "https://mp.weixin.qq.com/s/pLmuGoc4bZrMNl7MSoWgiA"
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response = requests.get(image_url)
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document = PyQuery(response.text)
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content = document('#js_content').text()
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sender = input('输入发件人邮箱地址:')
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password = getpass.getpass('输入发件人邮箱密码(可复制粘贴):')
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recipient = input('输入收件人邮箱地址:')
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def stats(url):
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response = requests.get(url)
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document = PyQuery(response.text)
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content = document('#js_content').text()
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yag = yagmail.SMTP(user=sender,password=password,host='smtp.qq.com')
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content = [stats_word.stats_text_cn(content,100)]
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yag.send(recipient,'lidong2119 d11',content)
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statList = stats_word.stats_text(content,100)
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statString = ''.join(str(i) for i in statList)
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return statString

19100101/lidong2119/d12_training2.py

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from wxpy import *
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import d11_training1
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bot = Bot()
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my_friend = bot.friends().search('伟仪',sex=FEMALE,city='深圳')[0]
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my_friend.send('请小叶子分享文章')
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@bot.register(my_friend)
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def get_msg(msg):
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if msg.type == 'Sharing':
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target_url = msg.url
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stats_msg = d11_training1.stats(target_url)
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msg.reply(stats_msg)
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else:
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pass
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embed()

19100101/qiming09/README.md

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2019.3.29
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1. learn to use 3rd-party libraby "wxpy".
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2. use "wxpy" to get others' message, analysis this message and reply the result.
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2019.3.28
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1. learn to use 3rd-party library "requests","yagmail","pyquery".
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2. use "requests" to get information from a url, get the content, cut the words and email them.

19100101/qiming09/d11_training1.py

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# author by : qiming
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import requests
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import yagmail
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import getpass
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from pyquery import PyQuery
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from mymodule import stats_word
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# 设置发件人、登录密码、收件人
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sender = input('请输入发件人邮箱地址:')
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psw = input('请输入发件人邮箱登录密码:')
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recipient = input('请输入收件人邮箱地址:')
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smtp = 'smtp.163.com'
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# 访问url获取微信公众号文章
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response = requests.get('https://mp.weixin.qq.com/s/pLmuGoc4bZrMNl7MSoWgiA')
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# 定义stats函数,通过url获取文本并分析
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def stats (url) :
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response = requests.get(url)
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# 提取微信公众号正文
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document = PyQuery (response.text)
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content = document ('#js_content').text()
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# 统计前100词频
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statList = stats_word.stats_text(content,100)
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statString = ''.join(str(i) for i in statList)
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return statString
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# 提取微信公众号正文
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document = PyQuery (response.text)
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content = document ('#js_content').text()
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# 统计前100词频
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statList = stats_word.stats_text(content,100)
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statString = ''.join(str(i) for i in statList)
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# 发送邮件功能的实现方法(暂不需要)
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# import yagmail
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# import getpass
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# 设置发件人、登录密码、收件人
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# sender = input('请输入发件人邮箱地址:')
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# psw = input('请输入发件人邮箱登录密码:')
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# recipient = input('请输入收件人邮箱地址:')
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# smtp = 'smtp.163.com'
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# 将统计结果发送到 [email protected],title: 19100101 qiming
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yagmail.SMTP(sender,psw,smtp).send(recipient,'19100101 qiming',statString)
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# yagmail.SMTP(sender,psw,smtp).send(recipient,'19100101 qiming',statString)

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