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def _find_key(self, key):
index = self._hash(key)
_len = len(self._table)
while self._table[index] is not HashTable.UNUSED:
if self._table[index] is HashTable.EMPTY:
index = (index*5 + 1) % _len
continue
elif self._table[index].key == key:
return index
else:
index = (index*5 + 1) % _len
return None
如果此时 len=8,table里有5个有效值3个EMPTY没有UNUSED,此时find的key不是5个有效值之一,那不是就永远不会退出while了吗?
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