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Isn't indirect mutable aliasing also undefined behavior? #50

@lokegustafsson

Description

@lokegustafsson

Consider the following program

use elsa::FrozenMap;
use std::cell::UnsafeCell;

fn main() {
    with_elsa();
    manual();
}

fn with_elsa() {
    // Within the second `insert` call, we are at the same time holding
    // - `&usize`
    // - `&mut HashMap<u8, Box<usize>>` (when calling entry() in insert impl)
    // Seems like UB?
    let v: FrozenMap<u8, Box<usize>> = Default::default();
    let a = v.insert(1, Box::new(1));
    let b = v.insert(2, Box::new(2));
    println!("{a} {b}");
}

fn manual() {
    // This is basically what is happening inside FrozenMap.
    let target: UnsafeCell<Box<u32>> = UnsafeCell::new(Box::new(1));
    let x = get_x(&target);
    let mut y = get_y(&target);
    // `x` and `y` are now (indirectly in the case of `y`) aliasing!
    // And `y` is mutable. Seems like UB?
    println!("{x} {y}");
    // Although `y` is short lived and the Box is never dereferenced.
    // Maybe this saves us from UB?
    let _ = y;
    let _ = x;
}

fn get_x<'a>(target: &'a UnsafeCell<Box<u32>>) -> &'a u32 {
    unsafe { &**target.get() }
}

fn get_y<'a>(target: &'a UnsafeCell<Box<u32>>) -> &'a mut Box<u32> {
    unsafe { &mut *target.get() }
}

This is totally fine according to miri but to my understanding of the aliasing rules it seems like basically every program using elsa has UB.

This could be avoided by using an inner hashmap that has a *mut self parameter rather than &mut self for its member methods (for example map.entry(key)). But I guess this is purely theoretical UB anyway, not causing miscompilations (or failing miri) in practice.

EDIT: I guess UnsafeCell<HashMap<K, UnsafeCell<V>>> could work, but maybe that has performance implications 🤷

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