fizzbuzz, Flatten the array and Remove the duplicates from array program added

Author: Kirttinath

fizzbuzz.js

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+//* Write a function that prints the numbers from 1 to 100. But for multiples of three print "Fizz" instead of the number and for the multiples of five print "Buzz". For numbers which are multiples of both three and five print "FizzBuzz".
+
+const FizzBuzz = () => {
+  for (let i = 1; i <= 100; i++) {
+    if (i % 15 === 0) {
+      console.log(i);
+    } else if (i % 3 === 0) {
+      console.log("Fizz");
+    } else if (i % 5 === 0) {
+      console.log("Buzz");
+    } else {
+      console.log(i);
+    }
+  }
+};
+
+FizzBuzz();

flattenArray.js

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+//* Write a function to flatten a nested array.
+const arr = [1, [2, 3, [5, [6, 9], 7], 8], 6];
+
+const Flatten_Array = (arr) => {
+  let Flt_arr = [];
+  for (let i = 0; i <= arr.length - 1; i++) {
+    if (Array.isArray(arr[i])) {
+      Flt_arr = Flt_arr.concat(Flatten_Array(arr[i]));
+    } else {
+      Flt_arr.push(arr[i]);
+    }
+  }
+  return Flt_arr;
+};
+
+const result_array = Flatten_Array(arr);
+
+console.log(result_array);

removeDup.js

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+const arr = [1, 2, 2, 3, 3, 4, 6, 5, 6, 8, 9, 3, 5];
+
+const remove_duplicate = (arr) => {
+  const unique = [];
+
+  for (let i = 0; i <= arr.length - 1; i++) {
+    if (unique.indexOf(arr[i]) === -1) {
+      unique.push(arr[i]);
+    }
+  }
+  return unique;
+};
+
+const result_unique = remove_duplicate(arr);
+console.log(result_unique.sort()); //? [ 1, 2, 3, 4, 5, 6, 8, 9 ]
+console.log(result_unique.sort((a, b) => b - a));