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PyJulia broken with Julia 1.5.2 Python 3.8? #425
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For reference, here is the same code successfully running with Python 3.8 and Julia 1.4.2
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This is likely the same as #424 and if so it would be solved by JuliaPy/PyCall.jl#841 |
I'm getting the same error when not running
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Is there any fix for this? |
I uninstalled and reinstalled both julia and PyCall, and although don't a segmentation error as before, I do get the same error message as @opus111 in the original post. Moreover, note that my python version is 3.7.6. Could I fix this by updating any package through github? |
Maybe I can help a bit. But I think not...
I tried this "test" multiple times: same result. Then I tried your "code":
Et voilá it works. I don't know why, just started with Julia. But maybe this helps getting some insight in this problem. Btw. maybe now it's "fixed", and it runs, if you ignore compiled_modules. Maybe someone with more insight can provide help / details. |
I am unable to replicate this issue. Python 3.9.1 in a virtualenv, Julia 1.5.3 acquired through Fedora package manager, installed PyCall from Julia's REPL and then in IPython ran: import julia These commands completed successfully. Note I did not use conda here (at least, not in purpose --- I gather that PyCall uses conda under the hood somewhere, based on the output it generates). |
Hello, I installed Julia 1.5.2 and tried to call it from Python. It failed on the "Julia( compiled_modules=False )"
To reproduce in Python call
Full log below
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