Merge pull request openAOD#918 from VipinChaudhary31/main

Issue  Symbol Pattern 169, Numeric pattern 232 and 233 solved

Author: aryashah2k

Numeric Patterns/numericpattern232.py

@@ -0,0 +1,12 @@
+for i in range(1,6):
+    for j in range(1,6):
+        if i==int(5/2)+1 or j==int(5/2)+1:
+            if abs(i-j)==2:
+                print(1,end=' ')
+            elif abs(i-j)==1:
+                print(2,end=' ')
+            else:
+                print(3,end=' ')
+        else:
+            print(" ",end=' ')
+    print(end='\n')

Numeric Patterns/numericpattern233.py

@@ -0,0 +1,7 @@
+for i in range(1,6):
+    for j in range(1,6):
+        if i==int(5/2)+1 or j==int(5/2)+1:
+            print(abs(i-j),end=' ')
+        else:
+            print(" ",end=' ')
+    print(end='\n')

Symbol Patterns/symbolicpattern169.py

@@ -0,0 +1,11 @@
+n=max=5
+symbol_arr=[4,3,5,1,2]
+for i in range(max):
+    for j in range(n):
+        if symbol_arr[j] >= max-i:
+            print(' # ',end='')
+        else:
+            print('   ', end='')
+    print(end='\n')
+for i in range(n):
+    print([i+1],end='')