huntober code challenges in python 2023

Author: IntelliJinceTech

huntober2023/fizzbuzz.py

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+# Given a number as an input, print out every integer from 1 to that number. However, when the integer is divisible by 3, print out “Fizz”; when it’s divisible by 5, print out “Buzz”; when it’s divisible by both 3 and 5, print out “Fizz Buzz”.
+
+# input is a number integer
+# output are strings 
+# 15 = "Fizz Buzz"
+# 3 = "Fizz"
+# 5 = "Buzz"
+
+def fizz_buzz_printer(num):
+    for n in range(num):
+        if n % 5 == 0 and n % 3 == 0 and n != 0:
+            print("Fizz Buzz")
+        elif n % 3 == 0:
+            print("Fizz")
+        elif n % 5 == 0: 
+            print("Buzz")
+        # print(n)
+            
+
+print(fizz_buzz_printer(16))