argMaxIf.md

slug	title	description	keywords	sidebar_label
/examples/aggregate-function-combinators/argMaxIf	argMaxIf	Example of using the argMaxIf combinator	argMax if combinator examples argMaxIf	argMaxIf

argMaxIf {#argmaxif}

Description {#description}

The If combinator can be applied to the argMax function to find the value of arg that corresponds to the maximum value of val for rows where the condition is true, using the argMaxIf aggregate combinator function.

The argMaxIf function is useful when you need to find the value associated with the maximum value in a dataset, but only for rows that satisfy a specific condition.

Example Usage {#example-usage}

In this example, we'll use a sample dataset of product sales to demonstrate how argMaxIf works. We'll find the product name that has the highest price, but only for products that have been sold at least 10 times.

CREATE TABLE product_sales
(
    product_name String,
    price Decimal32(2),
    sales_count UInt32
) ENGINE = Memory;

INSERT INTO product_sales VALUES
    ('Laptop', 999.99, 10),
    ('Phone', 499.99, 15),
    ('Tablet', 299.99, 0),
    ('Watch', 199.99, 5),
    ('Headphones', 79.99, 20);

SELECT argMaxIf(product_name, price, sales_count >= 10) as most_expensive_popular_product
FROM product_sales;

The argMaxIf function will return the product name that has the highest price among all products that have been sold at least 10 times (sales_count >= 10). In this case, it will return 'Laptop' since it has the highest price (999.99) among the popular products.

   ┌─most_expensi⋯lar_product─┐
1. │ Laptop                   │
   └──────────────────────────┘

See also {#see-also}

• argMax
• argMin
• argMinIf
• If combinator