Description
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
_______6______
/ \
___2__ ___8__
/ \ / \
0 _4 7 9
/ \
3 5
For example, the lowest common ancestor (LCA) of nodes 2
and 8
is 6
. Another example is LCA of nodes 2
and 4
is 2
, since a node can be a descendant of itself according to the LCA definition.
Thinking Process
- If p.val and q.val are both larger or smaller than root.val, they must be on the same side of the root
- Other wise, they are on different side of root, return root
Code
class Solution {
public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
if((p.val - root.val) * (q.val - root.val) <= 0){
return root;
}else if(p.val < root.val){
return lowestCommonAncestor(root.left, p, q);
}else{
return lowestCommonAncestor(root.right, p, q);
}
}
}